Integrand size = 32, antiderivative size = 31 \[ \int \frac {(d+e x)^5}{\left (c d^2+2 c d e x+c e^2 x^2\right )^{5/2}} \, dx=\frac {\sqrt {c d^2+2 c d e x+c e^2 x^2}}{c^3 e} \]
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Time = 0.02 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.062, Rules used = {657, 643} \[ \int \frac {(d+e x)^5}{\left (c d^2+2 c d e x+c e^2 x^2\right )^{5/2}} \, dx=\frac {\sqrt {c d^2+2 c d e x+c e^2 x^2}}{c^3 e} \]
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Rule 643
Rule 657
Rubi steps \begin{align*} \text {integral}& = \frac {\int \frac {d+e x}{\sqrt {c d^2+2 c d e x+c e^2 x^2}} \, dx}{c^2} \\ & = \frac {\sqrt {c d^2+2 c d e x+c e^2 x^2}}{c^3 e} \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.65 \[ \int \frac {(d+e x)^5}{\left (c d^2+2 c d e x+c e^2 x^2\right )^{5/2}} \, dx=\frac {\sqrt {c (d+e x)^2}}{c^3 e} \]
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Time = 2.52 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.71
method | result | size |
risch | \(\frac {\left (e x +d \right ) x}{c^{2} \sqrt {c \left (e x +d \right )^{2}}}\) | \(22\) |
pseudoelliptic | \(\frac {\left (e x +d \right )^{2}}{\sqrt {c \left (e x +d \right )^{2}}\, c^{2} e}\) | \(26\) |
default | \(\frac {x \left (e x +d \right )^{5}}{\left (c \,x^{2} e^{2}+2 x c d e +c \,d^{2}\right )^{\frac {5}{2}}}\) | \(32\) |
trager | \(\frac {x \sqrt {c \,x^{2} e^{2}+2 x c d e +c \,d^{2}}}{c^{3} \left (e x +d \right )}\) | \(35\) |
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Time = 0.30 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.23 \[ \int \frac {(d+e x)^5}{\left (c d^2+2 c d e x+c e^2 x^2\right )^{5/2}} \, dx=\frac {\sqrt {c e^{2} x^{2} + 2 \, c d e x + c d^{2}} x}{c^{3} e x + c^{3} d} \]
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Time = 0.34 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.35 \[ \int \frac {(d+e x)^5}{\left (c d^2+2 c d e x+c e^2 x^2\right )^{5/2}} \, dx=\begin {cases} \frac {\sqrt {c d^{2} + 2 c d e x + c e^{2} x^{2}}}{c^{3} e} & \text {for}\: e \neq 0 \\\frac {d^{5} x}{\left (c d^{2}\right )^{\frac {5}{2}}} & \text {otherwise} \end {cases} \]
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Leaf count of result is larger than twice the leaf count of optimal. 197 vs. \(2 (29) = 58\).
Time = 0.20 (sec) , antiderivative size = 197, normalized size of antiderivative = 6.35 \[ \int \frac {(d+e x)^5}{\left (c d^2+2 c d e x+c e^2 x^2\right )^{5/2}} \, dx=\frac {e^{3} x^{4}}{{\left (c e^{2} x^{2} + 2 \, c d e x + c d^{2}\right )}^{\frac {3}{2}} c} - \frac {4 \, c^{2} d^{5} e^{4}}{\left (c e^{2}\right )^{\frac {9}{2}} {\left (x + \frac {d}{e}\right )}^{4}} - \frac {6 \, d^{2} e x^{2}}{{\left (c e^{2} x^{2} + 2 \, c d e x + c d^{2}\right )}^{\frac {3}{2}} c} + \frac {32 \, c d^{4} e^{3}}{3 \, \left (c e^{2}\right )^{\frac {7}{2}} {\left (x + \frac {d}{e}\right )}^{3}} - \frac {17 \, d^{4}}{3 \, {\left (c e^{2} x^{2} + 2 \, c d e x + c d^{2}\right )}^{\frac {3}{2}} c e} - \frac {8 \, d^{3} e^{2}}{\left (c e^{2}\right )^{\frac {5}{2}} {\left (x + \frac {d}{e}\right )}^{2}} + \frac {4 \, d^{5}}{\left (c e^{2}\right )^{\frac {5}{2}} {\left (x + \frac {d}{e}\right )}^{4}} \]
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Time = 0.29 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.42 \[ \int \frac {(d+e x)^5}{\left (c d^2+2 c d e x+c e^2 x^2\right )^{5/2}} \, dx=\frac {x}{c^{\frac {5}{2}} \mathrm {sgn}\left (e x + d\right )} \]
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Timed out. \[ \int \frac {(d+e x)^5}{\left (c d^2+2 c d e x+c e^2 x^2\right )^{5/2}} \, dx=\int \frac {{\left (d+e\,x\right )}^5}{{\left (c\,d^2+2\,c\,d\,e\,x+c\,e^2\,x^2\right )}^{5/2}} \,d x \]
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